
Okay. I understand what gear ratios do.
However, I have a vague idea of the relationship between final drive ratio and individual gear ratios.
The following is just my assumptions on how things work, so it is very possibly wrong.

I would imagine that the final drive would be the engine RPM/wheel RPM if you were in a 1:1 gear ratio. So it is basically the gearing reduction achieved by the differential, rather than the individual gears. So if you had no gearbox, just an engine connected up to the driveshaft, the ratio of engine RPM/Wheel RPM would be equivilent to the final drive ratio.
Correct?
Here is some random gearbox information.
Gear Ratios:
5th (0.82): 3.53:1
4th (0.97): 4.18:1
3rd (1.31): 5.65:1
2nd (1.90): 8.19:1
1st (3.70): 13.66:1
Final Drive Ratio: 4.13:1
How would I work out the wheel RPM from the engine RPM in a given gear?
Would this be engine RPM/gear ratio/final drive?
There are two numbers listed there for the gear ratios. I would imagine that the one in brackets is the 'adjusted' ratio. (gear ratio/final drive) And the next number is the 'real' gear ratio.
Am I correct? Or am I completely wrong perhaps.

Thanks
Roman