Snwtoy,
I hope you get a response from someone who knows what they're talking about.

Unfortunately that's not me. I
think that just adding resistance in series will work but your diagram is not quite correct. You need to connect either the wire going into the pot, or the wire coming out, to the
wiper of the pot (the arrow) to wire it as a variable resistor.
However:
1)Don't do this unless you are sure that the wiring only powers the lights in the gauges -- otherwise the gauges will read funny.
2)Remember that the resistor will have to dissipate all the power that's not going to the gauge. I don't know how much that would be, but I'd guess that an ordinary potentiometer will probably not do. Maybe a more expensive wirewound pot would be enough -- I think Dick(head)Smith has ones rated at 5W. Otherwise you might be better off paralleling high power non-variable resistors.
I can't see why you'd need a relay unless you want it to be switched along with another circuit, such as the headlights. Darlingtons are not sensors but a type of transistor arrangement. You wouldn't want any diodes in this circuit.
A more elegant, and slightly more complicated circuit might use a voltage regulator chip.